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1z0-071 High Quality | Valid 1z0-071 Test Notes

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Oracle 1z1-071 (Oracle Database SQL) Exam is designed for professionals who want to show their skills and knowledge in SQL. 1z0-071 exam measures a candidate's ability to design, manage, and manipulate the Oracle database system's SQL language. Passing 1z0-071 Exam is a prerequisite for many Oracle certification programs.

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Oracle Database SQL Sample Questions (Q66-Q71):

NEW QUESTION # 66
View the exhibit and examine the structure of the PROMOTIONS table.

You have to generate a report that displays the promo name and start date for all promos that started after the last promo in the 'INTERNET' category.
Which query would give you the required output?

A. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date > ALL (SELECT promo_begin_dateFROM promotionsWHERE promo_category = 'INTERNET');
B. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date> ALL (SELECT MAX (promo_begin_date)FROM promotions) ANDpromo_category= 'INTERNET';
C. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date> ANY (SELECT promo_begin_dateFROM promotionsWHERE promo_category= 'INTERNET');
D. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date IN (SELECT promo_begin_dateFROM promotionsWHERE promo_category= 'INTERNET');

Answer: A

NEW QUESTION # 67
Examine the description of the CUSTOMERS table:

Which three statements will do an implicit conversion?

A. SELECT * FROM customers WHERE TO_ CHAR (customer_ id) = '0001';
B. SELECT FROM customers WHERE insert date = '01-JAN-19';
C. SELECT * FROM customers WHERE customer id = '0001';
D. SELECT * FROM customers WHERE customer_ id = 0001;
E. SELECT. FRON customers WE TO DATE (Insert _ date) = DATE '2019-01-01';
F. SELECT. FROM customers WHERE insert_ date = DATE *2019-01-01';

Answer: B,C,F

Explanation:
A: No implicit conversion is done here because TO_CHAR is an explicit conversion from a numeric to a string data type.
B: Implicit conversion happens here because the '0001' string will be automatically converted to a numeric data type to match the CUSTOMER_ID field.
C: No implicit conversion is needed because 0001 is already a numeric literal.
D: Implicit conversion occurs here because the string '01-JAN-19' will be converted to a date type to compare with INSERT_DATE.
E: No implicit conversion; DATE is explicitly specified using the DATE keyword.
F: Incorrect syntax, it has typographical errors and also TO_DATE is an explicit function, not an implicit conversion.
Reference for SQL functions, conversions, and the CROSS JOIN behavior can be found in the Oracle Database SQL Language Reference 12c documentation.

NEW QUESTION # 68
What is true about non-equijoin statement performance?

A. Table aliases can improve performance.
B. The BETWEEN condition always performs better than using the >= and <= conditions.
C. The join syntax used makes no difference to performance.
D. The Oracle join syntax performs better than the SQL:1999 compliant ANSI join syntax.
E. The BETWEEN condition always performs less well than using the >= and <= conditions.

Answer: A,C

NEW QUESTION # 69
Examine this statement which executes successfully:
Which three are true?

A. Regardless of salary,only if the employee id is less than 125,insert EMPLOYEE_ID,NANAGER_ID,SALARY into the MGR_HISTORY table.
B. Regardless of salary and employee id,insert EMPLOYEE_ID,MANAGER_ID,and SALARY into the MGR_HISTORY table.
C. If the salary is more than 20000 and the employee is less than 125,insert EMPLOYEE_ID and SALARY into the SPECIAL_SAL table.
D. Only if the salary is 20000 or less and the employee id is less than 125,insert EMPLOYEE_ID,MANAGER_ID,and SALARY into the MGR_HISTORY table.
E. If the salary is 20000 or less and the employee id is less than 125,insert EMPLOYEE_ID,HIRE_DATE,and SALARY into the SAL_HISTORY table.
F. Only if the salary is 20000 or less and the employee id is 125 or higher,insert EMPLOYEE_ID,MANAGER_ID,and SALARY into the MDR_HISTORY table.

Answer: A,D,E

Explanation:
The question describes a scenario with multiple conditional statements about data manipulation based on certain criteria related to employee_id and salary. The options detail different conditions and corresponding actions (insertions into various tables). Given the conditions specified in each option, here are the accurate answers based on logical deduction as Oracle SQL does not directly define these scenarios; instead, it provides the mechanisms (like IF conditions, WHERE clauses, etc.) to implement such logic:
* Option A: Regardless of salary, only if the employee id is less than 125, insert EMPLOYEE_ID, MANAGER_ID, SALARY into the MGR_HISTORY table.
* This is logically plausible as it specifies a simple condition on the employee ID without regard to salary. If true, it directs an insertion of specific columns into a history table, which is a common practice for recording details of a subset of employees based on certain criteria (like employee_id in this case).
* Option C: Only if the salary is 20000 or less and the employee id is less than 125, insert EMPLOYEE_ID, MANAGER_ID, and SALARY into the MGR_HISTORY table.
* Similar to option A, this statement combines two conditions (on salary and employee_id), focusing on a specific subset of employees for history recording. The combined conditionality aligns with typical SQL practices for managing and logging specific data subsets based on multiple criteria.
* Option E: If the salary is 20000 or less and the employee id is less than 125, insert EMPLOYEE_ID, HIRE_DATE, and SALARY into the SAL_HISTORY table.
* This condition again deals with specific attributes (salary and employee_id) to determine which data (including the HIRE_DATE) goes into another history table. The inclusion of HIRE_DATE suggests tracking changes or states over time, which is common in employee management systems.

NEW QUESTION # 70
View the Exhibit and examine the structure of ORDERS and CUSTOMERStables.

There is only one customer with the cust_last_namecolumn having value Roberts. Which INSERT statement should be used to add a row into the ORDERStable for the customer whose CUST_LAST_NAMEis Robertsand CREDIT_LIMITis 600?

A. INSERT INTO orders (order_id, order_data, order_mode,
(SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND
credit_limit=600), order_total)
VALUES(1, '10-mar-2007', 'direct', &&customer_id, 1000);
B. INSERT INTO(SELECT o.order_id, o.order_date, o.order_mode, c.customer_id, o.order_total FROM orders o, customers c WHERE o.customer_id = c.customer_id AND c.cust_last_name='Roberts' AND c.credit_limit=600 ) VALUES (1, '10-mar-2007', 'direct', (SELECT customer_id FROM customers WHERE cust_last_name='Roberts' AND credit_limit=600), 1000);
C. INSERT INTO orders
VALUES(1, '10-mar-2007', 'direct',
(SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND
credit_limit=600), 1000);
D. INSERT INTO orders (order_id, order_data, order_mode,
(SELECT customer_id
FROM customers
WHERE cust_last_name='Roberts' AND
credit_limit=600), order_total)
VALUES (1, '10-mar-2007', 'direct', &customer_id, 1000).

Answer: C

Explanation:
Explanation

NEW QUESTION # 71
......

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